Menghitung Jumlah Network dan Host Dari Alamat IP Adrees
Tugas
Pertemuan 2 (Jaringan Komputer)
Desi
Puspita Sari 19211119
19.7F.28
Soal:
Hitunglah
jumlah Network dan Host yang akan terbentuk dari alamat IP Address dibawah ini,
kemudian buat rincian alamat (Network, Broadcast) beserta alamat yang dapat
diberikan kepada host/komputer :
1. 192.168.10.1/30
2. 172.168.10.1/16
3. 172.168.10.0/22
4. 10.168.5.1/8
5. 10.168.5.1/17
Jawaban :
1. 192.168.10.1/30
Netmask :
255.255.255.252
Binary : 11111111. 11111111.
11111111.11111100 : /30
Network : 2n Host : 2h -2
:
26 : 22 - 2
: 64 Network
:
2 Host
Block Subnet : 256 – 252 = 4 Subnet.
4 + 4 = 8 + 4 = 12 + 4 =
16 Jadi 0, 4, 8, 12,16
|
|
Network
0 |
Network
1 |
Network
2 |
|
Subnet |
192.168.10.0 |
192.168.10.4 |
192.168.10.8 |
|
Host
Pertama |
192.168.10.1 |
192.168.10.5 |
192.168.10.9 |
|
Host
Terakhir |
192.168.10.2 |
192.168.10.6 |
192.168.10.14 |
|
Broadcast |
192.168.10.3 |
192.168.10.7 |
192.168.10.15 |
2. 172.168.10.1/16
Netmask :
255.255.0.0
Binary : 11111111. 11111111.
00000000.00000000 : /16
Network : 2n Host : 2h -2
:
20 : 216
- 2
:
1 Network : 65534 Host
Block Subnet : 256 – 128 = 128 Subnet.
128 + 128 = 256 + 128 =
384 Jadi 0, 128, 256, 384
|
|
Network
0 |
Network
1 |
Network
2 |
|
Subnet |
192.168.10.0 |
172.168.10.128 |
172.168.10.256 |
|
Host
Pertama |
192.168.10.1 |
172.168.10.129 |
172.168.10.257 |
|
Host
Terakhir |
172.168.10.126 |
172.168.10.254 |
172.168.10.382 |
|
Broadcast |
172.168.10.127 |
172.168.10.255 |
172.168.10.383 |
3. 172.168.10.1/22
Netmask :
255.255.252.0
Binary : 11111111. 11111111.
11111100.00000000 : /22
Network : 2n Host : 2h -2
:
26 : 210 -
2
:
64 Network : 1022 Host
Block Subnet : 256 – 252 = 4 Subnet.
4 + 4 = 8 + 4 = 12
jadi 0, 4, 8, 12
|
|
Network
0 |
Network
1 |
Network
2 |
|
Subnet |
172.168.10.0 |
172.168.10.4 |
172.168.10.8 |
|
Host
Pertama |
172.168.10.1 |
172.168.10.5 |
172.168.10.9 |
|
Host
Terakhir |
172.168.10.2 |
172.168.10.6 |
172.168.10.10 |
|
Broadcast |
172.168.10.3 |
172.168.10.7 |
172.168.10.11 |
4. 10.168.5.1/8
Netmask :
255.0.0.0
Binary : 11111111. 00000000 .
00000000.00000000 : /8
Network : 2n Host : 2h
-2
: 20 : 224 - 2
: 1 Network : 16777214 Host
Block Subnet : 256 – 0 = 256 / 0 (Karena Blok Subnet
256 Invalid, Jadi Blok Subnetnya : 0)
|
|
Network
0 |
|
Subnet |
10.0.0.0 |
|
Host
Pertama |
10.0.0.1 |
|
Host
Terakhir |
10.255.255.254 |
|
Broadcast |
10.255.255.255 |
5. 10.168.5.1/17
Netmask :
255.255.128.0
Binary : 11111111. 11111111.
10000000.00000000 : /17
Network : 2n Host : 2h
-2
: 21 : 215 - 2
: 2 Network : 32766 Host
Block Subnet 256 -
128 = 128 + 128 = 256 + 128 = 384 jadi 0, 128, 256, 384
|
|
Network
0 |
Network
1 |
Network
2 |
|
Subnet |
10.168.5.0 |
10.168.5.128 |
10.168.5.256 |
|
Host
Pertama |
10.168.5.1 |
10.168.5.129 |
10.168.5.257 |
|
Host
Terakhir |
10.168.5.126 |
10.168.5.254 |
10.168.5.382 |
|
Broadcast |
10.168.5.127 |
10.168.5.255 |
10.168.5.383 |
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